Guide · rigging — in development

Spreader Beam Design Calculator — the guide

For the people who own the lift plan: how a spreader differs from a lifting beam, why the sling angle is the most consequential number on the rigging sketch, what usually breaks an I-section spreader, and how to read what this tool tells you — including the questions it refuses to guess at. The companion methodology page explains every check and clause; this page teaches the physics first and the tool second.

Guide 01

Spreader beam or lifting beam?

Two different structural jobs that look alike from a distance. Which one you have decides what can go wrong.

A spreader beam hangs from two inclined top slings that meet at the hook. The slings' horizontal components squeeze the beam from both ends, so the beam works as a compression strut — its enemy is buckling, not bending. A lifting beam hangs from a single lug (or a pair close together) and carries its load points in bending — its enemy is the moment diagram. EN 13155's own definitions (§3.8) make the relationship explicit: a lifting beam whose loading is purely compressive is the same device the trade calls a spreader beam.

Spreader beam vs lifting beamFigure F2

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Spreader beam and lifting beam comparedLeft: a spreader with two inclined top slings meeting at a hook, the beam working as a compression strut, needing headroom for the sling triangle. Right: a single-lug lifting beam working in bending, suiting low headroom.Spreader beamloadheadroomN: compressionLifting beamloadlow headroomM: bendingsame engine, two structural jobs: a strut between inclined slings, or a beam hung from one lug
Left: two top slings to one hook — the beam is a compression strut, and the sling triangle needs headroom. Right: one lug, beam in bending — heavier steel for the same lift, but it works under a low hook.

The practical trade is headroom. A spreader needs vertical room for its sling triangle — steeper slings mean a taller triangle — and rewards you with a light, efficient strut. A lifting beam works right under the hook where a crane's height is exhausted, and pays for it in bending steel. When the headroom exists, the spreader usually wins on weight; when it does not, the lifting beam is the honest choice, and its moment diagram deserves respect.

Guide 02

Sling angles rule everything

One angle sets the force in the sling AND the force in the beam. Flat slings punish both at once.

For a symmetric two-sling spreader with hook load and sling angle from the horizontal, statics gives each leg and puts of compression into the beam. Both denominators collapse as the slings flatten:

Per-leg sling tension and beam compression, normalised by hook load, against sling angle.
α from horizontalT/W per legN/W in the beam
90°0.5000.000
60°0.5770.289
45°0.7070.500
30°1.0000.866
20°1.4621.374
What flattening the slings costsFigure F3

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Sling tension and beam compression against sling angleTwo curves computed from the statics identities: per-leg sling tension over hook load, and beam compression over hook load, both rising steeply as the sling angle from the horizontal falls below 45 degrees. Small beam-and-sling pictograms under the axis show a steep, a 45 degree, and a flat rig.force ÷ hook load Wsling angle α from the horizontal20°30°45°60°90°0.51.045° — DNV-ST-N001 §16.3.4.2: should generally be ≥ 45°T/W — tension per legN/W — beam compressionsteep — kind to everything45° — the customary floorflat — punishes sling AND beam
Computed from the statics identities at this render. The customary 45° floor — DNV-ST-N001 §16.3.4.2 says sling angles should generally be at least 45° — sits where both curves start steepening: below it, every degree costs real force in the sling and the beam simultaneously.

At 90° each sling carries half the load and the beam carries nothing axially. At 30° each sling carries the full hook load and the beam carries almost 87 % of it in compression. At 20° the numbers are 1.46 W per leg and 1.37 W in the beam — the rig is fighting itself. This is why flat slings punish both components: the same trigonometry sits in both denominators.

The constraint that flattens slings in practice is headroom: a hook that cannot go high enough forces a wide, shallow triangle. That is a real constraint, not a mistake — but it should be priced, and the tool prices it: enter the geometry you actually have, and the solved angles, tensions and compression land in the checks, with your declared minimum angle enforced and a written warning when the flattest sling drops below 30°.

Guide 03

Why weak-axis buckling usually governs an I-section spreader

A strut buckles about its weakest axis over its longest unbraced length — and a suspended spreader is unbraced from end to end.

An I-section is superb at bending about its major axis and mediocre as a strut: its weak-axis radius of gyration is typically a small fraction of . A column in a building often gets away with this because girts, purlins or slabs brace the weak axis at intervals. A spreader hanging in the air has no such friends: nothing braces a suspended beam between its end slings, so the full span, times the same effective-length factor, works on the weakest radius. The Euler stress falls with — halve the radius and the elastic buckling resistance drops fourfold.

Weak-axis buckling, and why tubes winFigure F9

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Weak-axis buckling of an I-section against a circular tubeAn I-section and a circular hollow section of comparable area, with the I-section's small weak-axis radius of gyration annotated against the tube's single radius. Below, a plan view of the strut bowing sideways about its weak axis in a single half-wave, with nothing bracing it between the end slings.I-sectiontwo radii: rx large, ry smallry is a fraction of rx — the weak axis buckles firstCircular hollow sectionone radius r, every directionno weak axis, and no lateral-torsional buckling branchplan view of the suspended strut — same KL for both sectionsnothing braces a suspended spreader between its end slings — the weakest r governs over the full lengthwhich is why the market's default spreader is a tube
Same axial force, same unbraced length. The I-section buckles about its weak axis at a fraction of its strong-axis capacity; the tube has one radius in every direction, no weak axis to find — and no lateral-torsional buckling branch either.

A circular tube has one radius of gyration in every direction and is exempt from lateral-torsional buckling on every route this tool computes — which is why the market's default spreader is a CHS. An I-section spreader is not wrong; it is simply a design whose governing check is usually weak-axis flexural buckling, and whose lateral-torsional behaviour depends on a question most tools never ask.

Guide 04

The tool solves the hang — what that buys you

Enter geometry, not conclusions. The angle, the tilt, the force senses and the couples all come out of the solve — including three effects an assumed-angle spreadsheet cannot represent.

Solved tilt, not assumed level. An off-centre centre of gravity tilts the hang until the hook sits over the effective CoG. The solver finds that attitude as a constrained minimum of potential energy, reports the tilt against your declared limit, and resolves self-weight and every sling force at the solved angle — so a CoG surprise shows up in the numbers, not on the site.

Tension detection. Splay the bottom slings outboard of the beam's lugs and the bottom rigging pulls the beam ends outward: the beam goes into tension, and the compression checks are the wrong checks. Most spreader tools cannot represent this arrangement at all. This one detects the sense from the solve and runs the right checks, spelling the sense out in words — for the default spreader, 30.7 kN of compression.

The eccentricity ledger. A padeye on a flange face cannot have its pin on the beam's neutral axis. Each pin's horizontal force component acting at its offset applies a transfer couple that jumps the moment diagram — on the default spreader, 4.61 kN·m at each end against a self-weight-only moment of 3.60 kN·m. Zeroing the eccentricities halves this beam's real midspan moment out of the model — the methodology page draws it.

The tilt case nobody sketchesFigure F5

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Level hang against the 6 degree design-tilt attitudeTwo panels. Level: the hook force and the load force act on one vertical line through the centred lug, and only self-weight bends the beam. At 6 degrees of tilt the two force lines separate by about 31 millimetres, driving a local shear spike and a higher peak moment.Level hangforces collinearloadmax |M| = 3.60 kN·m · V 2.4 kNHeld at the 6° design tilt≈31 mm between the force lines103.4 kN up98.6 kN down|V|max 100.5 kN · max |M| 5.13 kN·m — up 42%the effect EN 13155 §5.1.2.3 exists to catch — an assumed-angle spreadsheet never sees the force pair separate
A centred single-lug lifting beam, solved at this render. Level: forces collinear, max |M| = 3.60 kN·m of self-weight hogging. Held at the EN route's mandatory ±6°: the top force line and bottom pin separate by about 31 mm, and that force pair drives |V|max to 100.5 kN and max |M| to 5.13 kN·m — 42 % more bending than the level case, from a geometry change no assumed-angle spreadsheet ever sees.

The story in that figure is worth retelling in words, because it is the best single argument for solving the hang. Level, the centred lifting beam is as benign as rigging gets — the hook force and the load force share one line, and the beam carries only its own weight in bending. Tip the assembly six degrees, as EN 13155 requires you to assume it can be tipped, and the closure walks 31 mm away from the pin: suddenly a 103-kilonewton force pair acts across a short lever arm, shear jumps 42-fold, and the peak moment grows by 42 %. The clause exists precisely for this effect, and a spreadsheet that assumes its angle will never see it.

Guide 05

Choosing your assessment route

The route is a jurisdiction and client-specification question first, an engineering question second. Each route states its own honesty label.

Route decision flowFigure F8

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Choosing an assessment routeA flowchart: the jurisdiction or client specification selects the ASME, EN hybrid, or CSA hybrid route; a side branch asks whether the lift is marine and, if so, turns the DNV overlay on. Footnotes flag the hybrid labels and the AS placeholder.Jurisdiction / client specwhat does the lift plan cite?US practice · ASMEdesigns to BTH-1-2020with B30.20 obligationsEuropean practice · ENEN HYBRID — 13155 loads,EN 1993 resistancesCanadian practice · CSACSA HYBRID — S16-09 witha declared load factor αfMarine lift?DNV-ST-N001 overlay ON — any routehybrid = the load side or the companion chain sits outside theassessment, and the route says so instead of implying compliance
Start from what the lift plan cites. The DNV overlay is a side decision — marine lifts stack it on whichever route judges the steel.
  • ASME. Designs to ASME BTH-1-2020 — design categories, service classes, allowable stresses, fatigue, and the suspended-beam lateral-torsional reduction. The one fully self-contained route, with B30.20's marking and proof obligations reported alongside.
  • EN hybrid. EN 13155:2020 load conditions — withstand 2 × without permanent deformation, 3 × without releasing the load, plus the mandatory ±6° tilt case — on EN 1993 resistances. Labelled EN HYBRID because EN 13155's own calculation annex nominates the EN 13001 chain, which is outside this assessment; the label is printed wherever the route appears.
  • CSA hybrid. CSA S16-09 factored resistances against demands carrying a load factor you declare, because S16 takes its load factors from the NBCC and Canada has no below-the-hook standard. The route gates until the factor is declared — no default is invented.
  • DNV overlay. For marine lifts to DNV-ST-N001: DAF from the standard's table at the solved hook load, the skew factor under its own validity rules, and a fixed consequence factor of 1.30 for spreaders. It multiplies demands on any route, with a written warning where the combination double-counts dynamics.

Guide 06

Reading your results

The tool answers with three states, a named governing check, and a ledger of every factor it applied. Here is how to read each.

  • The status strip. PASS, FAIL or INDETERMINATE. INDETERMINATE is not a soft fail: it means a check refused to answer outside its provision — a designed gate with a named reason and remedy, listed in full on the methodology page. A FAIL always outranks a gate.
  • The governing check, named by station. Not just “utilisation 0.51” but which check, at which pin or station, in words. And the governing check is not always steel: on the default spreader the overall governing item is the sling-angle margin at 0.759 — the solved 59.3° against the declared 45° floor — while the largest strength utilisation is the padeye attachment weld — bth-1 §3-3.4 at 0.557. Both are named, which is exactly the kind of thing worth knowing before ordering steel.
  • The factor ledger. Every demand-side and resistance-side factor, each with its clause, printed in the report. An auditor reads the ledger instead of reconstructing the arithmetic.
  • The capacity envelope. WLL against span at utilisation 1.00, every point a genuine re-solve. A flat plateau means a connection governs — span is free until a member check takes over, and the redesign target is the padeye, not the beam. See the methodology page for the self-consistency test behind the curve.
  • Warnings, and accept-and-record. Warnings that are engineering judgements — an unusually flat sling, a CoG above the lift points — can be accepted. An acceptance is an input: it rides the share link and prints in the report with its timestamp while its condition holds. Nothing is dismissed into silence.

Guide 07

Worked example — the default 10 t spreader

The case the calculator opens with, walked end to end. Every number here is the engine's own output at this render; the same case is hand-verified on the verification record.

The rig: a symmetric 6 m spreader in CHS 273×12.7 (S355), 10 t rated load below the beam plus 0.5 kN of bottom rigging, hook 5.2 m above the beam axis, end lugs with 150 mm pin offsets, vertical 2 m bottom slings.

  1. The solve. Beam self-weight 4.80 kN brings the hook load to 103.40 kN. The top slings solve to 60.13 kN each at 59.3° from the horizontal — comfortably above the 45° floor — with a horizontal component of 30.71 kN per sling.
  2. The forces. The beam carries 30.71 kN of compression between the lugs. The moment diagram jumps by the H·e couple of 4.61 kN·m at each end and peaks at 8.20 kN·m at midspan; shear peaks at 2.40 kN.
  3. ASME route (Category B, Service Class 0). Member utilisations are small — axial 0.037 at 3.17 MPa, bending 0.104 at 13.52 MPa, combined 0.141 — and the connection carries the largest strength utilisations: weld 0.557, pin bearing 0.508, pinhole tension 0.251. The tube's manufacture is declared unknown, so the route designs on the §3-1.7 reduced wall.
  4. The same steel on the EN hybrid route tells the same story in different factors: the yielded (3 ×) condition governs through the padeye pin at 0.624, with the weld at 0.596. The member barely notices; the connection is the design.
  5. And on the CSA hybrid route at a declared load factor of 1.50: compression utilisation 0.021, bending 0.045, interaction 0.066, pin chain up to 0.295 — governed by the padeye weld at 0.310. Three routes, three factor systems, one conclusion: this design is connection-governed.

Guide 08

Practical pre-lift checklist

Ten lines to run before trusting any spreader calculation — this tool's or anyone's.

  1. Rated load, rigging weight and beam self-weight all in the hook load.
  2. Centre of gravity position confirmed from drawings or weighing — not assumed centred.
  3. Padeye pin eccentricities taken from the fabrication drawing, not set to zero.
  4. Sling angle floor declared, and the solved angles checked against it.
  5. Declared shares entered for any arrangement with more than two bottom points.
  6. End twist restraint declared honestly — a shackle braces nothing.
  7. Route factors declared: category and service class, cycle count, or the project load factor.
  8. Hollow-section manufacture declared, so the right wall thickness designs the ASME route.
  9. Proof-load and marking obligations for the jurisdiction identified and assigned.
  10. Every accepted warning reviewed in the report — an acceptance is a recorded decision.

Guide 09

Frequently asked questions

Why does the tool refuse my 4-point lift?
Four bottom points on rigid bodies are statically indeterminate: the sharing depends on sling stretch and fabrication tolerance, which the model deliberately does not include. Equal sharing is an assumption, not a solution — real 4-point lifts routinely carry most of the load on a diagonal pair. Enter the declared shares from your rigging analysis and the tool computes with them, printed as your declaration.
Why is my result INDETERMINATE instead of FAIL?
FAIL means a computed check exceeded its capacity. INDETERMINATE means a check could not honestly compute — a provision's validity limits were exceeded, a required declaration is missing, or the arrangement did not solve. The result names the gate and the remedy. Treating a refusal as a soft pass, or as a fail, would both be wrong: it is a question the tool is handing back to you.
Why can't I edit the DNV consequence factor?
Because DNV-ST-N001 does not offer a choice: Table 16-5 row 1 assigns 1.30 to spreader frames and beams not subjected to load testing, and a load-tested spreader keeps 1.30 as a lift-point attachment under §16.8.5.1. Either reading lands on 1.30, so it is printed, sourced, and not a knob.
Why does the EN route run a ±6° case I didn't ask for?
EN 13155 §5.1.2.3 requires attachments not intended to tilt to be designed for at least 6° of tilt — and §5.2.6.3.1 says a lifting beam for horizontal use shall tolerate 6°. The tool re-closes the statics at that attitude and envelopes the demands, because on some geometries the tilt case adds nothing and on others it dominates the shear diagram entirely. Section 4 of this guide shows one of the second kind.
Why doesn't my capacity drop when I increase the span?
Because a connection governs. A padeye weld's capacity does not know the span, so the WLL-versus-span curve runs flat until a member check — buckling or bending — takes over. The plateau is the design insight: to lift more, fix the connection, not the beam.
Which route should I pick in Canada?
Canada has no below-the-hook device standard, so there is no route that removes the decision from you. The CSA hybrid route judges the steel to S16-09's factored resistances, and asks you to declare the demand-side load factor your project basis requires — because S16 itself takes load factors from the NBCC, which is a building code, not a lifting standard. Many projects also accept a BTH-1 design; that is a specification question for the lift plan's owner.
Spreader Beam Design Calculator — user guide · Xarpis